Solved Arai60/122. Best Time to Buy and Sell Stock II#38
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Solved Arai60/122. Best Time to Buy and Sell Stock II#38
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…t Time to Buy and Sell Stock II.md
Fuminiton
reviewed
Aug 5, 2025
| for i in range(1, len(prices)): | ||
| price_diff = prices[i] - prices[i-1] | ||
| if price_diff > 0: | ||
| profit += price_diff |
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いいと思いました。
完全に趣味ですが、price_diffよりはprofitの方が好みでした。差に関する変数だという意味にプラスして、当日-前日なのか、前日-当日なのかが伝わる気がするので。
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確かにそういう考え方もありますね、ありがとうございます！
Mike0121
reviewed
Aug 24, 2025
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| - ある点までの利益とその後の利益を足す？ | ||
| - 何回も足す必要があるしO(n)を何回かやることになる | ||
| - よく考えると上がるところを全部計上すれば良いだけ |
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これに気づけると楽ですよね。自分は、この手の少し算数的(貪欲法)な問題は各パターンを手書きして考えてみています。
Mike0121
reviewed
Aug 24, 2025
| class Solution: | ||
| def maxProfit(self, prices: List[int]) -> int: | ||
| profit = 0 | ||
| buy = prices[0] |
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変数名、buyは、動詞単体のため少しわかりづらいと感じました。buy_priceなどはどうでしょうか？
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問題文：https://leetcode.com/problems/best-time-to-buy-and-sell-stock-ii/description/