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Merge_Intervals.cpp
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132 lines (121 loc) · 2.77 KB
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// Source : https://oj.leetcode.com/problems/merge-intervals/
// Author : zheng yi xiong
// Date : 2015-02-12
/**********************************************************************************
*
* Given a collection of intervals, merge all overlapping intervals.
* For example,
* Given [1,3],[2,6],[8,10],[15,18],
* return [1,6],[8,10],[15,18].
*
**********************************************************************************/
#include "stdafx.h"
#include <iostream>
#include <vector>
using namespace std;
struct Interval {
int start;
int end;
Interval() : start(0), end(0) {}
Interval(int s, int e) : start(s), end(e) {}
};
class Solution {
public:
vector<Interval> merge(vector<Interval> &intervals) {
if (intervals.empty())
{
return intervals;
}
vector<Interval> ret_intervals;
ret_intervals.push_back(intervals.front());
for (vector<Interval>::iterator it = intervals.begin() + 1; it != intervals.end(); ++it)
{
if (ret_intervals.back().end < it->start)
{
ret_intervals.push_back(*it);
}
else if (ret_intervals[0].start > it->end)
{
ret_intervals.insert(ret_intervals.begin(), *it);
}
else if (ret_intervals[0].start > it->start && (ret_intervals.back().end < it->end))
{
ret_intervals.clear();
ret_intervals.push_back(*it);
}
else
{
bool bFindStart = false;
for (vector<Interval>::iterator ret_it = ret_intervals.begin(); ret_it != ret_intervals.end(); )
{
if ( (!bFindStart) && (it->start <= ret_it->end) )
{
if (it->end < ret_it->start)
{
ret_intervals.insert(ret_it, *it);
break;
}
else if (it->start <= ret_it->start)
{
ret_it->start = it->start;
if (it->end <= ret_it->end)
{
break;
}
ret_it->end = it->end;
}
else if (it->end <= ret_it->end)
{
break;
}
else
{
ret_it->end = it->end;
}
bFindStart = true;
++ret_it;
}
else if (bFindStart)
{
if (ret_it->start > it->end)
{
break;
}
else if (ret_it->end < it->end)
{
ret_it = ret_intervals.erase(ret_it);
}
else
{
it->end = ret_it->end;
ret_it = ret_intervals.erase(ret_it);
--ret_it;
ret_it->end = it->end;
break;
}
}
else
{
++ret_it;
}
}
}
}
return ret_intervals;
}
};
int _tmain(int argc, _TCHAR* argv[])
{
vector<Interval> intervals(4);
intervals[0].start = 1;
intervals[0].end = 3;
intervals[1].start = 2;
intervals[1].end = 6;
intervals[2].start = 8;
intervals[2].end = 10;
intervals[3].start = 15;
intervals[3].end = 18;
Solution so;
vector<Interval> ret = so.merge(intervals);
return 0;
}