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Gray_Code.cpp
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70 lines (57 loc) · 1.58 KB
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// Source : https://oj.leetcode.com/problems/gray-code/
// Author : zheng yi xiong
// Date : 2015-01-06
/**********************************************************************************
*
* The gray code is a binary numeral system where two successive values differ in only one bit.
* Given a non-negative integer n representing the total number of bits in the code, print the sequence of gray code. A gray code sequence must begin with 0.
* For example, given n = 2, return [0,1,3,2]. Its gray code sequence is:
* 00 - 0
* 01 - 1
* 11 - 3
* 10 - 2
* Note:
* For a given n, a gray code sequence is not uniquely defined.
* For example, [0,2,3,1] is also a valid gray code sequence according to the above definition.
* For now, the judge is able to judge based on one instance of gray code sequence. Sorry about that.
*
**********************************************************************************/
#include "stdafx.h"
#include <iostream>
#include <vector>
using namespace std;
class Solution {
public:
vector<int> grayCode(int n) {
vector<int> vec_gray;
if (0 >= n)
{
vec_gray.push_back(0);
return vec_gray;
}
vec_gray.push_back(0);
vec_gray.push_back(1);
int prev_len = 2;
int add_value = 0;
for (int i = 1; i < n; ++i)
{
add_value = 0x1 << i;
for (int j = prev_len - 1; j >= 0; --j)
{
vec_gray.push_back(vec_gray[j] + add_value);
}
prev_len <<= 1;
}
return vec_gray;
}
};
int _tmain(int argc, _TCHAR* argv[])
{
int n = 3;
if ( argc > 1) {
n = _wtoi(argv[1]);
}
Solution so;
vector<int> vec_int = so.grayCode(n);
return 0;
}