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Binary_Tree_Maximum_Path_Sum.cpp
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121 lines (97 loc) · 2.15 KB
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// Source : https://oj.leetcode.com/problems/binary-tree-maximum-path-sum/
// Author : zheng yi xiong
// Date : 2014-12-15
/**********************************************************************************
*
* Given a binary tree, find the maximum path sum.
* The path may start and end at any node in the tree.
* For example:
* Given the below binary tree,
* 1
* / \
* 2 3
* Return 6.
*
**********************************************************************************/
#include "stdafx.h"
#include <string>
using namespace std;
struct TreeNode {
int val;
TreeNode *left;
TreeNode *right;
TreeNode(int x) : val(x), left(NULL), right(NULL) {}
};
class Solution {
private:
int maxSonPath(TreeNode *pParent, int &maxPath)
{
int maxSon = pParent->val;
int leftPath = 0;
int rightPath = 0;
if (maxPath < pParent->val)
{
maxPath = pParent->val;
}
if (NULL != pParent->left)
{
leftPath = maxSonPath(pParent->left, maxPath);
if (maxPath < leftPath + pParent->val)
{
maxPath = leftPath + pParent->val;
}
if (maxSon < leftPath + pParent->val)
{
maxSon = leftPath + pParent->val;
}
}
if (NULL != pParent->right)
{
rightPath = maxSonPath(pParent->right, maxPath);
if (maxPath < rightPath + pParent->val)
{
maxPath = rightPath + pParent->val;
}
if (maxSon < rightPath + pParent->val)
{
maxSon = rightPath + pParent->val;
}
}
if (maxPath < leftPath + rightPath + pParent->val)
{
maxPath = leftPath + rightPath + pParent->val;
}
return maxSon;
}
public:
int maxPathSum(TreeNode *root) {
if (NULL == root)
{
return 0;
}
int maxPath = root->val;
int leftPath = 0;
int rightPath = 0;
if (NULL != root->left)
{
leftPath = maxSonPath(root->left, maxPath);
if (maxPath < leftPath + root->val)
{
maxPath = leftPath + root->val;
}
}
if (NULL != root->right)
{
rightPath = maxSonPath(root->right, maxPath);
if (maxPath < rightPath + root->val)
{
maxPath = rightPath + root->val;
}
}
if (maxPath < leftPath + rightPath + root->val)
{
maxPath = leftPath + rightPath + root->val;
}
return maxPath;
}
};