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133.clone-graph.java
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94 lines (84 loc) · 2.46 KB
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import java.util.HashMap;
import java.util.Map;
import org.w3c.dom.Node;
/*
* @lc app=leetcode id=133 lang=java
*
* [133] Clone Graph
*
* https://leetcode.com/problems/clone-graph/description/
*
* algorithms
* Medium (29.13%)
* Likes: 1106
* Dislikes: 1120
* Total Accepted: 264.5K
* Total Submissions: 883.2K
* Testcase Example: '{"$id":"1","neighbors":[{"$id":"2","neighbors":[{"$ref":"1"},{"$id":"3","neighbors":[{"$ref":"2"},{"$id":"4","neighbors":[{"$ref":"3"},{"$ref":"1"}],"val":4}],"val":3}],"val":2},{"$ref":"4"}],"val":1}'
*
* Given a reference of a node in a connected undirected graph, return a deep
* copy (clone) of the graph. Each node in the graph contains a val (int) and a
* list (List[Node]) of its neighbors.
*
*
*
* Example:
*
*
*
*
* Input:
*
* {"$id":"1","neighbors":[{"$id":"2","neighbors":[{"$ref":"1"},{"$id":"3","neighbors":[{"$ref":"2"},{"$id":"4","neighbors":[{"$ref":"3"},{"$ref":"1"}],"val":4}],"val":3}],"val":2},{"$ref":"4"}],"val":1}
*
* Explanation:
* Node 1's value is 1, and it has two neighbors: Node 2 and 4.
* Node 2's value is 2, and it has two neighbors: Node 1 and 3.
* Node 3's value is 3, and it has two neighbors: Node 2 and 4.
* Node 4's value is 4, and it has two neighbors: Node 1 and 3.
*
*
*
*
* Note:
*
*
* The number of nodes will be between 1 and 100.
* The undirected graph is a simple graph, which means no repeated edges and no
* self-loops in the graph.
* Since the graph is undirected, if node p has node q as neighbor, then node q
* must have node p as neighbor too.
* You must return the copy of the given node as a reference to the cloned
* graph.
*
*/
// @lc code=start
/*
// Definition for a Node.
class Node {
public int val;
public List<Node> neighbors;
public Node() {}
public Node(int _val,List<Node> _neighbors) {
val = _val;
neighbors = _neighbors;
}
};
*/
class Solution {
public HashMap<Integer, Node> map = new HashMap<>();
public Node cloneGraph(Node node) {
return dfs(node);
}
public Node dfs(Node node) {
if (node == null) return null;
if (map.containsKey(node.val))
return map.get(node.val);
Node newNode = new Node(node.val, new ArrayList<Node>());
map.put(newNode.val, newNode);
for (Node neighbor : node.neighbors)
newNode.neighbors.add(dfs(neighbor));
return newNode;
}
}
// @lc code=end