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ValidPalindrome.java
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executable file
·30 lines (25 loc) · 1.01 KB
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/**
Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.
For example,
"A man, a plan, a canal: Panama" is a palindrome.
"race a car" is not a palindrome.
Note:
Have you consider that the string might be empty? This is a good question to ask during an interview.
For the purpose of this problem, we define empty string as valid palindrome.
Hide Tags Two Pointers String
*/
public class ValidPalindrome {
public boolean isPalindrome(String s) {
if (s == null || s.trim().isEmpty()) return true;
s = s.trim().toLowerCase();
int i = 0, j = s.length() - 1;
while (i < j) {
char left = s.charAt(i), right = s.charAt(j);
if ((left < 'a' || left > 'z') && (left < '0' || left > '9')) i++;
else if ((right < 'a' || right > 'z') && (right < '0' || right > '9')) j--;
else if (left != right) return false;
else { i++; j--; }
}
return true;
}
}