When using the lowest representable int value as a double in a conformance tests, the test passes whereas the std::numeric_limits<int64_t>::lowest() converted to a double will error. There needs to be a further look at the overflow behavior in C++ in this case.
When using the lowest representable int value as a double in a conformance tests, the test passes whereas the std::numeric_limits<int64_t>::lowest() converted to a double will error. There needs to be a further look at the overflow behavior in C++ in this case.